What is the center (x^2}{36}-\frac{y^2)/9 =1 ?

The center (x^2}{36}-\frac{y^2)/9 =1 is (0,0)

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center (x^2}{36}-\frac{y^2)/9 =1

center

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 3

And the center is:

(0, 0)

x^{2} - y^{2} - 2 x - 4 y = - 4

9 y^{2} - 4 x^{2} = 36

\frac{( x + 3 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

18 x^{2} - 32 y^{2} = 2

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

What is the center (x^2}{36}-\frac{y^2)/9 =1 ?
The center (x^2}{36}-\frac{y^2)/9 =1 is (0,0)