What is the center 18x^2-32y^2=2 ?

The center 18x^2-32y^2=2 is (0,0)

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center 18x^2-32y^2=2

center

18 x^{2} - 32 y^{2} = 2

(0, 0)

Solution steps

18 x^{2} - 32 y^{2} = 2

Rewrite

18 x^{2} - 32 y^{2} = 2

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{3} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{3}, b = \frac{1}{4}

And the center is:

(0, 0)

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

4 x^{2} - 9 y^{2} = 36

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

4 x^{2} - 9 y^{2} + 3 x + 18 y + 91 = 0