What is the center x^2-y^2-2x-4y=-4 ?

The center x^2-y^2-2x-4y=-4 is (1,-2)

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center x^2-y^2-2x-4y=-4

center

x^{2} - y^{2} - 2 x - 4 y = - 4

(1, - 2)

Solution steps

x^{2} - y^{2} - 2 x - 4 y = - 4

Rewrite

x^{2} - y^{2} - 2 x - 4 y = - 4

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{( 7 ) ^{2}} - \frac{( x - 1 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 7, b = 7

And the center is:

(1, - 2)

9 y^{2} - 4 x^{2} = 36

\frac{( x + 3 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

18 x^{2} - 32 y^{2} = 2

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1