What is the center (x^2)/(49)-(y^2)/(16)=1 ?

The center (x^2)/(49)-(y^2)/(16)=1 is (0,0)

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center (x^2)/(49)-(y^2)/(16)=1

center

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 4

And the center is:

(0, 0)

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

x^{2} - \frac{y ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

- \frac{( y - 3 ) ^{2}}{25} + \frac{( x + 2 ) ^{2}}{9} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

What is the center (x^2)/(49)-(y^2)/(16)=1 ?
The center (x^2)/(49)-(y^2)/(16)=1 is (0,0)