What is the center x^2-(y^2)/(16)=1 ?

The center x^2-(y^2)/(16)=1 is (0,0)

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center x^2-(y^2)/(16)=1

center

x^{2} - \frac{y ^{2}}{16} = 1

(0, 0)

Solution steps

x^{2} - \frac{y ^{2}}{16} = 1

Rewrite

x^{2} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 4

And the center is:

(0, 0)

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

- \frac{( y - 3 ) ^{2}}{25} + \frac{( x + 2 ) ^{2}}{9} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1