What is the center ((x-1)^2)/4-((y-2)^2)/1 =1 ?

The center ((x-1)^2)/4-((y-2)^2)/1 =1 is (1,2)

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center ((x-1)^2)/4-((y-2)^2)/1 =1

center

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

(1, 2)

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - 2 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 2, b = 1

And the center is:

(1, 2)

- \frac{( y - 3 ) ^{2}}{25} + \frac{( x + 2 ) ^{2}}{9} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

What is the center ((x-1)^2)/4-((y-2)^2)/1 =1 ?
The center ((x-1)^2)/4-((y-2)^2)/1 =1 is (1,2)