What is the foci (x^2)/((64/7))-(y^2)/((48/7))=1 ?

The foci (x^2)/((64/7))-(y^2)/((48/7))=1 is (4,0),(-4,0)

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foci (x^2)/((64/7))-(y^2)/((48/7))=1

foci

\frac{x ^{2}}{( \frac{64}{7} )} - \frac{y ^{2}}{( \frac{48}{7} )} = 1

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{\frac{64}{7}} - \frac{y ^{2}}{\frac{48}{7}} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = \frac{8}{7}, b = \frac{4 3}{7}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (\frac{8}{7})^{2} + (\frac{4 3}{7})^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

y^{2} - x^{2} = 36

y^{2} - x^{2} = 22

16 x^{2} - 96 x - 9 y^{2} + 36 y - 36 = 0

What is the foci (x^2)/((64/7))-(y^2)/((48/7))=1 ?
The foci (x^2)/((64/7))-(y^2)/((48/7))=1 is (4,0),(-4,0)