What is the foci 16x^2-96x-9y^2+36y-36=0 ?

The foci 16x^2-96x-9y^2+36y-36=0 is (8,2),(-2,2)

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foci 16x^2-96x-9y^2+36y-36=0

foci

16 x^{2} - 96 x - 9 y^{2} + 36 y - 36 = 0

(8, 2), (- 2, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

16 x^{2} - 96 x - 9 y^{2} + 36 y - 36 = 0 :

Right-left Hyperbola with

(h, k) = (3, 2), a = 3, b = 4

(3 + c, 2), (3 - c, 2)

Compute

c :

c = 3^{2} + 4^{2} : 5

(3 + 5, 2), (3 - 5, 2)

Refine

(8, 2), (- 2, 2)

\frac{x ^{2}}{4} - \frac{y ^{2}}{49} = 1

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{11} - \frac{( y + 1 ) ^{2}}{5} = 1

16 x^{2} - y^{2} - 96 x - 6 y + 119 = 0

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

What is the foci 16x^2-96x-9y^2+36y-36=0 ?
The foci 16x^2-96x-9y^2+36y-36=0 is (8,2),(-2,2)