What is the foci y^2-x^2=22 ?

The foci y^2-x^2=22 is (0,2sqrt(11)),(0,-2sqrt(11))

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foci y^2-x^2=22

foci

y^{2} - x^{2} = 22

(0, 211), (0, - 211)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - x^{2} = 22 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 22, b = 22

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 22^{2} + 22^{2} : 211

(0, 0 + 211), (0, 0 - 211)

Refine

(0, 211), (0, - 211)

16 x^{2} - 96 x - 9 y^{2} + 36 y - 36 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{49} = 1

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{11} - \frac{( y + 1 ) ^{2}}{5} = 1

16 x^{2} - y^{2} - 96 x - 6 y + 119 = 0

What is the foci y^2-x^2=22 ?
The foci y^2-x^2=22 is (0,2sqrt(11)),(0,-2sqrt(11))