What is the foci x^2-16y^2=144 ?

The foci x^2-16y^2=144 is (3sqrt(17),0),(-3sqrt(17),0)

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foci x^2-16y^2=144

foci

x^{2} - 16 y^{2} = 144

(317, 0), (- 317, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 16 y^{2} = 144 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 12, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 2^{2} + 3^{2} : 317

(0 + 317, 0), (0 - 317, 0)

Refine

(317, 0), (- 317, 0)

\frac{y ^{2}}{1 0 ^{2}} - \frac{x ^{2}}{2 4 ^{2}} = 1

\frac{y ^{2}}{18} - \frac{x ^{2}}{2} = 1

\frac{( y - 1 ) ^{2}}{\frac{1}{4}} - \frac{( x - 1 ) ^{2}}{\frac{1}{16}} = 1

\frac{( X - 8 ) ^{2}}{9} - \frac{( Y + 3 ) ^{2}}{16} = 1

4 x^{2} - 5 y^{2} - 32 x + 10 y + 79 = 0

What is the foci x^2-16y^2=144 ?
The foci x^2-16y^2=144 is (3sqrt(17),0),(-3sqrt(17),0)