What is the foci (y^2)/(10^2)-(x^2)/(24^2)=1 ?

The foci (y^2)/(10^2)-(x^2)/(24^2)=1 is (0,26),(0,-26)

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foci (y^2)/(10^2)-(x^2)/(24^2)=1

foci

\frac{y ^{2}}{1 0 ^{2}} - \frac{x ^{2}}{2 4 ^{2}} = 1

(0, 26), (0, - 26)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{1 0 ^{2}} - \frac{x ^{2}}{2 4 ^{2}} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 10, b = 24

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 0^{2} + 2 4^{2} : 26

(0, 0 + 26), (0, 0 - 26)

Refine

(0, 26), (0, - 26)

\frac{y ^{2}}{18} - \frac{x ^{2}}{2} = 1

\frac{( y - 1 ) ^{2}}{\frac{1}{4}} - \frac{( x - 1 ) ^{2}}{\frac{1}{16}} = 1

\frac{( X - 8 ) ^{2}}{9} - \frac{( Y + 3 ) ^{2}}{16} = 1

4 x^{2} - 5 y^{2} - 32 x + 10 y + 79 = 0

\frac{( x + 2 ) ^{2}}{64} - \frac{( y + 4 ) ^{2}}{81} = 1

What is the foci (y^2)/(10^2)-(x^2)/(24^2)=1 ?
The foci (y^2)/(10^2)-(x^2)/(24^2)=1 is (0,26),(0,-26)