What is the foci 4x^2-5y^2-32x+10y+79=0 ?

The foci 4x^2-5y^2-32x+10y+79=0 is (4,4),(4,-2)

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foci 4x^2-5y^2-32x+10y+79=0

foci

4 x^{2} - 5 y^{2} - 32 x + 10 y + 79 = 0

(4, 4), (4, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

4 x^{2} - 5 y^{2} - 32 x + 10 y + 79 = 0 :

Up-down Hyperbola with

(h, k) = (4, 1), a = 2, b = 5

(4, 1 + c), (4, 1 - c)

Compute

c :

c = 2^{2} + 5^{2} : 3

(4, 1 + 3), (4, 1 - 3)

Refine

(4, 4), (4, - 2)

\frac{( x + 2 ) ^{2}}{64} - \frac{( y + 4 ) ^{2}}{81} = 1

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

x^{2} - 3 y^{2} + 2 x + 6 y - 1 = 0

- 4 x^{2} + 25 y^{2} - 16 x - 116 = 0

x^{2} - y^{2} + 4 x - 2 y = - 2

What is the foci 4x^2-5y^2-32x+10y+79=0 ?
The foci 4x^2-5y^2-32x+10y+79=0 is (4,4),(4,-2)