What is the foci x^2-9y^2=36 ?

The foci x^2-9y^2=36 is (2sqrt(10),0),(-2sqrt(10),0)

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foci x^2-9y^2=36

foci

x^{2} - 9 y^{2} = 36

(210, 0), (- 210, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 9 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 2^{2} : 210

(0 + 210, 0), (0 - 210, 0)

Refine

(210, 0), (- 210, 0)

\frac{( y + 5 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{16} = 1

- x^{2} + \frac{y ^{2}}{20} = 1

x^{2} - 16 y^{2} = 144

\frac{y ^{2}}{1 0 ^{2}} - \frac{x ^{2}}{2 4 ^{2}} = 1

\frac{y ^{2}}{18} - \frac{x ^{2}}{2} = 1

What is the foci x^2-9y^2=36 ?
The foci x^2-9y^2=36 is (2sqrt(10),0),(-2sqrt(10),0)