What is the foci (y^2}{16}-\frac{x^2)/1 =1 ?

The foci (y^2}{16}-\frac{x^2)/1 =1 is (0,sqrt(17)),(0,-sqrt(17))

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foci (y^2}{16}-\frac{x^2)/1 =1

foci

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 1^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

y^{2} - 2 = x^{2} - 2 x

\frac{( x ) ^{2}}{\frac{25}{4}} - \frac{( y ) ^{2}}{\frac{11}{4}} = 1

\frac{x ^{2}}{4} - \frac{3 y ^{2}}{4} = 1

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

What is the foci (y^2}{16}-\frac{x^2)/1 =1 ?
The foci (y^2}{16}-\frac{x^2)/1 =1 is (0,sqrt(17)),(0,-sqrt(17))