What is the foci (y^2)/(36)-(x^2)/(16)=1 ?

The foci (y^2)/(36)-(x^2)/(16)=1 is (0,2sqrt(13)),(0,-2sqrt(13))

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foci (y^2)/(36)-(x^2)/(16)=1

foci

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

(0, 213), (0, - 213)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 4^{2} : 213

(0, 0 + 213), (0, 0 - 213)

Refine

(0, 213), (0, - 213)

\frac{( x + 1.6 ) ^{2}}{1} - \frac{( y + 1 ) ^{2}}{0.07} = 1

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

25 y^{2} - 36 (x - 8)^{2} = 900

\frac{y ^{2}}{16} - \frac{x ^{2}}{36} = 1

What is the foci (y^2)/(36)-(x^2)/(16)=1 ?
The foci (y^2)/(36)-(x^2)/(16)=1 is (0,2sqrt(13)),(0,-2sqrt(13))