What is the foci y^2-2=x^2-2x ?

The foci y^2-2=x^2-2x is (1,sqrt(2)),(1,-sqrt(2))

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foci y^2-2=x^2-2x

foci

y^{2} - 2 = x^{2} - 2 x

(1, 2), (1, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - 2 = x^{2} - 2 x :

Up-down Hyperbola with

(h, k) = (1, 0), a = 1, b = 1

(1, 0 + c), (1, 0 - c)

Compute

c :

c = 1^{2} + 1^{2} : 2

(1, 0 + 2), (1, 0 - 2)

Refine

(1, 2), (1, - 2)

\frac{( x ) ^{2}}{\frac{25}{4}} - \frac{( y ) ^{2}}{\frac{11}{4}} = 1

\frac{x ^{2}}{4} - \frac{3 y ^{2}}{4} = 1

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{16} = 1

\frac{( x + 1.6 ) ^{2}}{1} - \frac{( y + 1 ) ^{2}}{0.07} = 1

What is the foci y^2-2=x^2-2x ?
The foci y^2-2=x^2-2x is (1,sqrt(2)),(1,-sqrt(2))