What is the foci (y^2)/1-(x^2)/(15)=1 ?

The foci (y^2)/1-(x^2)/(15)=1 is (0,4),(0,-4)

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foci (y^2)/1-(x^2)/(15)=1

foci

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 15

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 15^{2} : 4

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

What is the foci (y^2)/1-(x^2)/(15)=1 ?
The foci (y^2)/1-(x^2)/(15)=1 is (0,4),(0,-4)