What is the foci 16y^2-32y-9x^2-18x=137 ?

The foci 16y^2-32y-9x^2-18x=137 is (-1,6),(-1,-4)

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foci 16y^2-32y-9x^2-18x=137

foci

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

(- 1, 6), (- 1, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137 :

Up-down Hyperbola with

(h, k) = (- 1, 1), a = 3, b = 4

(- 1, 1 + c), (- 1, 1 - c)

Compute

c :

c = 3^{2} + 4^{2} : 5

(- 1, 1 + 5), (- 1, 1 - 5)

Refine

(- 1, 6), (- 1, - 4)

\frac{x ^{2}}{9} - \frac{y ^{2}}{1} = 1

25 y^{2} - x^{2} = 100

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

\frac{x ^{2}}{36} - \frac{y ^{2}}{16} = 1

x^{2} - y^{2} = 49

What is the foci 16y^2-32y-9x^2-18x=137 ?
The foci 16y^2-32y-9x^2-18x=137 is (-1,6),(-1,-4)