What is the foci 9(x-1)^2-16(y+2)^2=144 ?

The foci 9(x-1)^2-16(y+2)^2=144 is (6,-2),(-4,-2)

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foci 9(x-1)^2-16(y+2)^2=144

foci

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

(6, - 2), (- 4, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144 :

Right-left Hyperbola with

(h, k) = (1, - 2), a = 4, b = 3

(1 + c, - 2), (1 - c, - 2)

Compute

c :

c = 4^{2} + 3^{2} : 5

(1 + 5, - 2), (1 - 5, - 2)

Refine

(6, - 2), (- 4, - 2)

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

\frac{x ^{2}}{9} - \frac{y ^{2}}{1} = 1

25 y^{2} - x^{2} = 100

What is the foci 9(x-1)^2-16(y+2)^2=144 ?
The foci 9(x-1)^2-16(y+2)^2=144 is (6,-2),(-4,-2)