What is the vertices-4x^2+y^2+8y-20=0 ?

The vertices-4x^2+y^2+8y-20=0 is (0,2),(0,-10)

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vertices-4x^2+y^2+8y-20=0

vertices

- 4 x^{2} + y^{2} + 8 y - 20 = 0

(0, 2), (0, - 10)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 4 x^{2} + y^{2} + 8 y - 20 = 0 :

Up-down Hyperbola with

(h, k) = (0, - 4), a = 6, b = 3

(0, - 4 + 6), (0, - 4 - 6)

Refine

(0, 2), (0, - 10)

\frac{y ^{2}}{25} - \frac{x ^{2}}{39} = 1

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

- 2 x^{2} + 5 y^{2} + 3 x + 8 y + 4 = 0

What is the vertices-4x^2+y^2+8y-20=0 ?
The vertices-4x^2+y^2+8y-20=0 is (0,2),(0,-10)