What is the vertices y^2-9x^2-8y-54x-81=0 ?

The vertices y^2-9x^2-8y-54x-81=0 is (-3,8),(-3,0)

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vertices y^2-9x^2-8y-54x-81=0

vertices

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0

(- 3, 8), (- 3, 0)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0 :

Up-down Hyperbola with

(h, k) = (- 3, 4), a = 4, b = \frac{4}{3}

(- 3, 4 + 4), (- 3, 4 - 4)

Refine

(- 3, 8), (- 3, 0)

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

- 2 x^{2} + 5 y^{2} + 3 x + 8 y + 4 = 0

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

(4 x - 3 y) = \frac{- 144}{( 4 x + 3 y )}

What is the vertices y^2-9x^2-8y-54x-81=0 ?
The vertices y^2-9x^2-8y-54x-81=0 is (-3,8),(-3,0)