What is the vertices (y^2)/(25)-(x^2)/(39)=1 ?

The vertices (y^2)/(25)-(x^2)/(39)=1 is (0,5),(0,-5)

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vertices (y^2)/(25)-(x^2)/(39)=1

vertices

\frac{y ^{2}}{25} - \frac{x ^{2}}{39} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{39} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 39

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

- 2 x^{2} + 5 y^{2} + 3 x + 8 y + 4 = 0

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

What is the vertices (y^2)/(25)-(x^2)/(39)=1 ?
The vertices (y^2)/(25)-(x^2)/(39)=1 is (0,5),(0,-5)