What is -(x^2)/(144)+(y^2)/(25)=1 ?

The solution to -(x^2)/(144)+(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=5,b=12

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-(x^2)/(144)+(y^2)/(25)=1

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 5, b = 12

Solution steps

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

Rewrite

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 12

\frac{( x - 4 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{25} = 1

y^{2} = \frac{4 x ^{2}}{9} - 9

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{( y - \frac{1}{4} ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

f (x) f (x) = \frac{15 x ^{3} - 3 x ^{2} - 12 x}{3 x}

What is -(x^2)/(144)+(y^2)/(25)=1 ?
The solution to -(x^2)/(144)+(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=5,b=12