What is y^2=(4x^2)/9-9 ?

The solution to y^2=(4x^2)/9-9 is Hyperbola with (h,k)=(0,0),a= 9/2 ,b=3

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y^2=(4x^2)/9-9

y^{2} = \frac{4 x ^{2}}{9} - 9

(h, k) = (0, 0), a = \frac{9}{2}, b = 3

Solution steps

y^{2} = \frac{4 x ^{2}}{9} - 9

Rewrite

y^{2} = \frac{4 x ^{2}}{9} - 9

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{9}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{9}{2}, b = 3

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{( y - \frac{1}{4} ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

f (x) f (x) = \frac{15 x ^{3} - 3 x ^{2} - 12 x}{3 x}

\frac{y ^{2}}{100} - \frac{x ^{2}}{49} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{33} = 1

What is y^2=(4x^2)/9-9 ?
The solution to y^2=(4x^2)/9-9 is Hyperbola with (h,k)=(0,0),a= 9/2 ,b=3