What is the axis (x^2)/9+(y^2)/(64)=1 ?

The axis (x^2)/9+(y^2)/(64)=1 is semi-major axis b=8, semi-minor axis a=3

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axis (x^2)/9+(y^2)/(64)=1

axis

\frac{x ^{2}}{9} + \frac{y ^{2}}{64} = 1

semi - major axis b = 8, semi - minor axis a = 3

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 3

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{x ^{2}}{3} + \frac{y ^{2}}{2} = 1

36 x^{2} + 9 y^{2} - 324 = 0

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

What is the axis (x^2)/9+(y^2)/(64)=1 ?
The axis (x^2)/9+(y^2)/(64)=1 is semi-major axis b=8, semi-minor axis a=3