What is the axis (x^2)/4+(y^2)/(25)=1 ?

The axis (x^2)/4+(y^2)/(25)=1 is semi-major axis b=5, semi-minor axis a=2

Popular >

axis (x^2)/4+(y^2)/(25)=1

axis

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

semi - major axis b = 5, semi - minor axis a = 2

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 2

4 x^{2} + 9 y^{2} - 8 x + 90 y + 193 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

5 x^{2} + 7 y^{2} = 35

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

What is the axis (x^2)/4+(y^2)/(25)=1 ?
The axis (x^2)/4+(y^2)/(25)=1 is semi-major axis b=5, semi-minor axis a=2