What is the axis 16x^2+25y^2-224x+250y=191 ?

The axis 16x^2+25y^2-224x+250y=191 is semi-major axis a=10, semi-minor axis b=8

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axis 16x^2+25y^2-224x+250y=191

axis

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

semi - major axis a = 10, semi - minor axis b = 8

Solution steps

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

Rewrite

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

in the form of the standard ellipse equation

\frac{( x - 7 ) ^{2}}{1 0 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (7, - 5), a = 10, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (7, - 5), a = 10, b = 8

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

4 x^{2} + 9 y^{2} - 8 x + 90 y + 193 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

5 x^{2} + 7 y^{2} = 35

What is the axis 16x^2+25y^2-224x+250y=191 ?
The axis 16x^2+25y^2-224x+250y=191 is semi-major axis a=10, semi-minor axis b=8