What is the foci 16x^2+25y^2-128x+150y+81=0 ?

The foci 16x^2+25y^2-128x+150y+81=0 is (7,-3),(1,-3)

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foci 16x^2+25y^2-128x+150y+81=0

foci

16 x^{2} + 25 y^{2} - 128 x + 150 y + 81 = 0

(7, - 3), (1, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 128 x + 150 y + 81 = 0 :

Ellipse with center

(h, k) = (4, - 3), a = 5, b = 4

(4 + c, - 3), (4 - c, - 3)

Compute

c :

c = 5^{2} - 4^{2} : 3

(4 + 3, - 3), (4 - 3, - 3)

Refine

(7, - 3), (1, - 3)

x^{2} + 4 y^{2} + 8 y = 0

16 x^{2} + 25 y^{2} - 96 x - 256 = 0

\frac{( ( x + 7 ) ^{2} )}{9} + \frac{( ( y - 4 ) ^{2} )}{7} = 1

9 x^{2} + y^{2} = 1

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{25} = 1

What is the foci 16x^2+25y^2-128x+150y+81=0 ?
The foci 16x^2+25y^2-128x+150y+81=0 is (7,-3),(1,-3)