What is the foci 16x^2+25y^2-96x-256=0 ?

The foci 16x^2+25y^2-96x-256=0 is (6,0),(0,0)

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foci 16x^2+25y^2-96x-256=0

foci

16 x^{2} + 25 y^{2} - 96 x - 256 = 0

(6, 0), (0, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 96 x - 256 = 0 :

Ellipse with center

(h, k) = (3, 0), a = 5, b = 4

(3 + c, 0), (3 - c, 0)

Compute

c :

c = 5^{2} - 4^{2} : 3

(3 + 3, 0), (3 - 3, 0)

Refine

(6, 0), (0, 0)

\frac{( ( x + 7 ) ^{2} )}{9} + \frac{( ( y - 4 ) ^{2} )}{7} = 1

9 x^{2} + y^{2} = 1

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{25} = 1

9 (x - 5)^{2} + 4 (y + 2)^{2} = 36

x^{2} \frac{1}{2} + y^{2} \frac{1}{4} = 1

What is the foci 16x^2+25y^2-96x-256=0 ?
The foci 16x^2+25y^2-96x-256=0 is (6,0),(0,0)