What is the foci (x^2}{81}+\frac{y^2)/4 =1 ?

The foci (x^2}{81}+\frac{y^2)/4 =1 is (sqrt(77),0),(-sqrt(77),0)

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foci (x^2}{81}+\frac{y^2)/4 =1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{4} = 1

(77, 0), (- 77, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 2^{2} : 77

(0 + 77, 0), (0 - 77, 0)

Refine

(77, 0), (- 77, 0)

25 x^{2} + 16 y^{2} - 150 x - 32 y - 159 = 0

\frac{( x + 6 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

9 x^{2} + y^{2} + 18 x - 4 y + 4 = 0

\frac{x ^{2}}{32} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{100} + \frac{( y - 6 ) ^{2}}{64} = 1

What is the foci (x^2}{81}+\frac{y^2)/4 =1 ?
The foci (x^2}{81}+\frac{y^2)/4 =1 is (sqrt(77),0),(-sqrt(77),0)