foki ((x^2)/4)+y^2=1

Lösung

foki

(\frac{x ^{2}}{4}) + y^{2} = 1

(3, 0), (- 3, 0)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{4} + y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} - 1^{2} : 3

(0 + 3, 0), (0 - 3, 0)

Fasse zusammen

(3, 0), (- 3, 0)

f oc i \frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

f oc i \frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

f oc i \frac{( x - 3 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{9} = 1

f oc i \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

f oc i x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0