foki (2x^2)/(25)+((y-3)^2)/(49)=1

Lösung

foki

\frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

(0, 3 + \frac{73}{2}), (0, 3 - \frac{73}{2})

Schritte zur Lösung

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 3), b = 7, a = \frac{5}{2}

(0, 3 + c), (0, 3 - c)

Compute

c :

c = 7^{2} - (\frac{5}{2})^{2} : \frac{73}{2}

(0, 3 + \frac{73}{2}), (0, 3 - \frac{73}{2})

f oc i \frac{( x - 3 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{9} = 1

f oc i \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

f oc i x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

f oc i 4 x^{2} + 25 y^{2} - 24 x + 250 y + 561 = 0

f oc i 5 x^{2} + 9 y^{2} - 20 x - 18 y - 16 = 0