foki 5x^2+9y^2-20x-18y-16=0

Lösung

foki

5 x^{2} + 9 y^{2} - 20 x - 18 y - 16 = 0

(4, 1), (0, 1)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

5 x^{2} + 9 y^{2} - 20 x - 18 y - 16 = 0 :

Ellipse with center

(h, k) = (2, 1), a = 3, b = 5

(2 + c, 1), (2 - c, 1)

Compute

c :

c = 3^{2} - 5^{2} : 2

(2 + 2, 1), (2 - 2, 1)

Fasse zusammen

(4, 1), (0, 1)

f oc i \frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

f oc i \frac{( x - 6 ) ^{2}}{36} + \frac{( y + 4 ) ^{2}}{16} = 1

f oc i 1 = \frac{( x - 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25}

f oc i \frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1

f oc i \frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1