foki ((x+3)^2)/4+((y-2)^2)/(16)=1

Lösung

foki

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

(- 3, 2 + 23), (- 3, 2 - 23)

Schritte zur Lösung

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (- 3, 2), b = 4, a = 2

(- 3, 2 + c), (- 3, 2 - c)

Compute

c :

c = 4^{2} - 2^{2} : 23

(- 3, 2 + 23), (- 3, 2 - 23)

f oc i \frac{( x - 6 ) ^{2}}{36} + \frac{( y + 4 ) ^{2}}{16} = 1

f oc i 1 = \frac{( x - 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{25}

f oc i \frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1

f oc i \frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1

f oc i 25 x^{2} + 4 y^{2} + 50 x - 16 y = 59