foki ((x-1)^2)/5+((y-3)^2)/4 =1

Lösung

foki

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1

(2, 3), (0, 3)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{5} + \frac{( y - 3 ) ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (1, 3), a = 5, b = 2

(1 + c, 3), (1 - c, 3)

Compute

c :

c = 5^{2} - 2^{2} : 1

(1 + 1, 3), (1 - 1, 3)

Fasse zusammen

(2, 3), (0, 3)

f oc i \frac{2 x ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

f oc i \frac{( x - 3 ) ^{2}}{2} + \frac{( y - 5 ) ^{2}}{9} = 1

f oc i \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

f oc i x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

f oc i 4 x^{2} + 25 y^{2} - 24 x + 250 y + 561 = 0