What is the foci (x^2)/4+(y^2)/(20)=1 ?

The foci (x^2)/4+(y^2)/(20)=1 is (0,4),(0,-4)

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foci (x^2)/4+(y^2)/(20)=1

foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{20} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{20} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 25, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (25)^{2} - 2^{2} : 4

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

\frac{( x 8 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{100} = 1

\frac{x ^{2}}{32} + \frac{y ^{2}}{18} = 1

x^{2} + \frac{y ^{2}}{100} = 1

\frac{( x - 2 ) ^{2}}{8 ^{2}} + \frac{( y + 2 ) ^{2}}{3 ^{2}} = 1

y^{2} = 1 - 49 x^{2}

What is the foci (x^2)/4+(y^2)/(20)=1 ?
The foci (x^2)/4+(y^2)/(20)=1 is (0,4),(0,-4)