What is the vertices 25x^2+9y^2+200x-90y+400=0 ?

The vertices 25x^2+9y^2+200x-90y+400=0 is (-4,10),(-4,0)

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vertices 25x^2+9y^2+200x-90y+400=0

vertices

25 x^{2} + 9 y^{2} + 200 x - 90 y + 400 = 0

(- 4, 10), (- 4, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 9 y^{2} + 200 x - 90 y + 400 = 0 :

Ellipse with center

(h, k) = (- 4, 5), b = 5, a = 3

(- 4, 5 + 5), (- 4, 5 - 5)

Refine

(- 4, 10), (- 4, 0)

9 x^{2} + 36 y^{2} + 36 x - 216 y + 36 = 0

9 x^{2} + 6 y^{2} + 36 y = 0

\frac{x ^{2}}{2} + \frac{y ^{2}}{3} = 1

x^{2} + 4 y^{2} - 6 x - 16 y = 36

(\frac{x + 5}{4})^{2} + (\frac{y - 4}{16})^{2} = 1

What is the vertices 25x^2+9y^2+200x-90y+400=0 ?
The vertices 25x^2+9y^2+200x-90y+400=0 is (-4,10),(-4,0)