What is the vertices (x^2)/(15)+(y^2)/(45)=1 ?

The vertices (x^2)/(15)+(y^2)/(45)=1 is (0,3sqrt(5)),(0,-3sqrt(5))

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vertices (x^2)/(15)+(y^2)/(45)=1

vertices

\frac{x ^{2}}{15} + \frac{y ^{2}}{45} = 1

(0, 35), (0, - 35)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{15} + \frac{y ^{2}}{45} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 35, a = 15

(0, 0 + 35), (0, 0 - 35)

Refine

(0, 35), (0, - 35)

\frac{x ^{2}}{4} + \frac{y ^{2}}{2} = 1

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

3 x^{2} + 2 y^{2} + 6 x - 4 y + 5 = 18

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{169} = 1

What is the vertices (x^2)/(15)+(y^2)/(45)=1 ?
The vertices (x^2)/(15)+(y^2)/(45)=1 is (0,3sqrt(5)),(0,-3sqrt(5))