foki 3x^2+y^2-24x+39=0

Lösung

foki

3 x^{2} + y^{2} - 24 x + 39 = 0

(4, 6), (4, - 6)

Schritte zur Lösung

(h, k + c), (h, k - c)

Calculate ellipse properties

3 x^{2} + y^{2} - 24 x + 39 = 0 :

Ellipse with center

(h, k) = (4, 0), b = 3, a = 3

(4, 0 + c), (4, 0 - c)

Compute

c :

c = 3^{2} - 3^{2} : 6

(4, 0 + 6), (4, 0 - 6)

Fasse zusammen

(4, 6), (4, - 6)

f oc i 9 x^{2} + 16 y^{2} + 126 x + 96 y + 441 = 0

f oc i 8 x^{2} + 2 y^{2} + 16 x = 0

f oc i 16 x^{2} + 25 y^{2} - 64 x - 50 y - 311 = 0

f oc i x^{2} - 8 x + 25 y^{2} - 100 y + 91 = 0

f oc i 25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0