What is the vertices 9x^2+4y^2-36x+40y+100=0 ?

The vertices 9x^2+4y^2-36x+40y+100=0 is (2,-2),(2,-8)

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vertices 9x^2+4y^2-36x+40y+100=0

vertices

9 x^{2} + 4 y^{2} - 36 x + 40 y + 100 = 0

(2, - 2), (2, - 8)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 4 y^{2} - 36 x + 40 y + 100 = 0 :

Ellipse with center

(h, k) = (2, - 5), b = 3, a = 2

(2, - 5 + 3), (2, - 5 - 3)

Refine

(2, - 2), (2, - 8)

9 x^{2} + 16 y^{2} + 96 y = 0

49 x^{2} + 25 y^{2} - 1225 = 0

16 x^{2} + 64 y^{2} = 128

\frac{x ^{2}}{4} + \frac{( y + 3 ) ^{2}}{9} = 1

16 y^{2} + 25 x^{2} - 80 x + 36 y + 80 = 0

What is the vertices 9x^2+4y^2-36x+40y+100=0 ?
The vertices 9x^2+4y^2-36x+40y+100=0 is (2,-2),(2,-8)