What is the vertices 49x^2+25y^2-1225=0 ?

The vertices 49x^2+25y^2-1225=0 is (0,7),(0,-7)

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vertices 49x^2+25y^2-1225=0

vertices

49 x^{2} + 25 y^{2} - 1225 = 0

(0, 7), (0, - 7)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

49 x^{2} + 25 y^{2} - 1225 = 0 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 5

(0, 0 + 7), (0, 0 - 7)

Refine

(0, 7), (0, - 7)

16 x^{2} + 64 y^{2} = 128

\frac{x ^{2}}{4} + \frac{( y + 3 ) ^{2}}{9} = 1

16 y^{2} + 25 x^{2} - 80 x + 36 y + 80 = 0

4 x^{2} + 9 y^{2} - 48 x + 72 y = - 144

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 2 ) ^{2}}{20} = 1

What is the vertices 49x^2+25y^2-1225=0 ?
The vertices 49x^2+25y^2-1225=0 is (0,7),(0,-7)