What is the vertices 4x^2+9y^2-16x-18y-11=0 ?

The vertices 4x^2+9y^2-16x-18y-11=0 is (5,1),(-1,1)

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vertices 4x^2+9y^2-16x-18y-11=0

vertices

4 x^{2} + 9 y^{2} - 16 x - 18 y - 11 = 0

(5, 1), (- 1, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 16 x - 18 y - 11 = 0 :

Ellipse with center

(h, k) = (2, 1), a = 3, b = 2

(2 + 3, 1), (2 - 3, 1)

Refine

(5, 1), (- 1, 1)

x^{2} + 3 y^{2} = 6

x^{2} + 3 y^{2} - 6 x + 6 y = 0

7 x^{2} + 9 y^{2} = 63

\frac{x ^{2}}{81} + \frac{y ^{2}}{225} = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

What is the vertices 4x^2+9y^2-16x-18y-11=0 ?
The vertices 4x^2+9y^2-16x-18y-11=0 is (5,1),(-1,1)