What is the vertices 25x^2+9y^2-200x-36y+211=0 ?

The vertices 25x^2+9y^2-200x-36y+211=0 is (4,7),(4,-3)

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vertices 25x^2+9y^2-200x-36y+211=0

vertices

25 x^{2} + 9 y^{2} - 200 x - 36 y + 211 = 0

(4, 7), (4, - 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 9 y^{2} - 200 x - 36 y + 211 = 0 :

Ellipse with center

(h, k) = (4, 2), b = 5, a = 3

(4, 2 + 5), (4, 2 - 5)

Refine

(4, 7), (4, - 3)

x^{2} + y^{2} + 6 x - 4 y - 3 = 0

\frac{x ^{2}}{100} + \frac{y ^{2}}{49} = 1

\frac{( x + 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{25} = 1

x^{2} + 2 y^{2} - 1 = 0

9 x^{2} + 25 y^{2} = 9

What is the vertices 25x^2+9y^2-200x-36y+211=0 ?
The vertices 25x^2+9y^2-200x-36y+211=0 is (4,7),(4,-3)