What is the vertices 9x^2-54x+y^2+2y+46=0 ?

The vertices 9x^2-54x+y^2+2y+46=0 is (3,5),(3,-7)

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vertices 9x^2-54x+y^2+2y+46=0

vertices

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

(3, 5), (3, - 7)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0 :

Ellipse with center

(h, k) = (3, - 1), b = 6, a = 2

(3, - 1 + 6), (3, - 1 - 6)

Refine

(3, 5), (3, - 7)

12 (x + 4)^{2} + 3 (y - 1)^{2} = 48

4 x^{2} + 25 y^{2} = 100

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0

3 x^{2} + 12 y^{2} - 6 x - 48 y + 33 = 0

36 x^{2} + 25 y^{2} = 900

What is the vertices 9x^2-54x+y^2+2y+46=0 ?
The vertices 9x^2-54x+y^2+2y+46=0 is (3,5),(3,-7)