What is the vertices 81x^2+4y^2=324 ?

The vertices 81x^2+4y^2=324 is (0,9),(0,-9)

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vertices 81x^2+4y^2=324

vertices

81 x^{2} + 4 y^{2} = 324

(0, 9), (0, - 9)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

81 x^{2} + 4 y^{2} = 324 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 2

(0, 0 + 9), (0, 0 - 9)

Refine

(0, 9), (0, - 9)

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

12 (x + 4)^{2} + 3 (y - 1)^{2} = 48

4 x^{2} + 25 y^{2} = 100

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0

What is the vertices 81x^2+4y^2=324 ?
The vertices 81x^2+4y^2=324 is (0,9),(0,-9)