What is the circumference (x-1/2)^2+(y+2/3)^2=5 ?

The circumference (x-1/2)^2+(y+2/3)^2=5 is C=2sqrt(5)pi

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circumference (x-1/2)^2+(y+2/3)^2=5

circumference

(x - \frac{1}{2})^{2} + (y + \frac{2}{3})^{2} = 5

C = 25 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - \frac{1}{2})^{2} + (y + \frac{2}{3})^{2} = 5 : r = 5

C = 25 π

2 (x - 3)^{2} + 2 y^{2} = 8

x^{2} + y^{2} \leq 25

(x + 6)^{2} + (y - 7)^{2} = 9

x^{2} + y^{2} - 6 x + 6 y - 7 = 0

9 x^{2} + 9 y^{2} - 6 x - 2 y - 14 = 0

What is the circumference (x-1/2)^2+(y+2/3)^2=5 ?
The circumference (x-1/2)^2+(y+2/3)^2=5 is C=2sqrt(5)pi