What is the radius x^2+y^2+18x+14y+105=0 ?

The radius x^2+y^2+18x+14y+105=0 is r=5

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radius x^2+y^2+18x+14y+105=0

radius

x^{2} + y^{2} + 18 x + 14 y + 105 = 0

r = 5

Solution steps

x^{2} + y^{2} + 18 x + 14 y + 105 = 0

Rewrite

x^{2} + y^{2} + 18 x + 14 y + 105 = 0

in the form of the standard circle equation

(x - (- 9))^{2} + (y - (- 7))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 9, - 7), r = 5

And the radius is:

r = 5

(x + 3)^{2} + (y + 5)^{2} = 4

(x + 12)^{2} + (y - 13)^{2} - 25 = 0

x^{2} + y^{2} + 2 x - 6 y - y = 0

(x + 1)^{2} + y^{2} = 246

5 x^{2} - 10 x + 5 y^{2} + 3 y - 7 = 0

What is the radius x^2+y^2+18x+14y+105=0 ?
The radius x^2+y^2+18x+14y+105=0 is r=5