What is the radius x^2-6x+14y-567+y^2=0 ?

The radius x^2-6x+14y-567+y^2=0 is r=25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2-6x+14y-567+y^2=0

radius

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

r = 25

Solution steps

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

Rewrite

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 7))^{2} = 2 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 7), r = 25

And the radius is:

r = 25

x^{2} + y^{2} + 2 x - 4 y - 4 = 0

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216

x^{2} + y^{2} - 4 x + 9 x = 16

(x + 2)^{2} + (y - 3)^{2} = (- 6)^{2}

x^{2} + y^{2} - 10 x + 4 y + 25 = 0

What is the radius x^2-6x+14y-567+y^2=0 ?
The radius x^2-6x+14y-567+y^2=0 is r=25