What is the radius (x+3)^2+(y+5)^2=4 ?

The radius (x+3)^2+(y+5)^2=4 is r=2

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radius (x+3)^2+(y+5)^2=4

radius

(x + 3)^{2} + (y + 5)^{2} = 4

r = 2

Solution steps

(x + 3)^{2} + (y + 5)^{2} = 4

Rewrite

(x + 3)^{2} + (y + 5)^{2} = 4

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 5))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 5), r = 2

And the radius is:

r = 2

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