What is the radius 74=(24-x)^2+(22-y)^2 ?

The radius 74=(24-x)^2+(22-y)^2 is r=sqrt(74)

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radius 74=(24-x)^2+(22-y)^2

radius

74 = (24 - x)^{2} + (22 - y)^{2}

r = 74

Solution steps

74 = (24 - x)^{2} + (22 - y)^{2}

Rewrite

74 = (24 - x)^{2} + (22 - y)^{2}

in the form of the standard circle equation

(x - 24)^{2} + (y - 22)^{2} = (74)^{2}

Therefore the circle properties are:

(a, b) = (24, 22), r = 74

And the radius is:

r = 74

(x - 1)^{2} + (y + 2)^{2} = 5

(x + 4)^{2} + (y + 3)^{2} = 16

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

x^{2} + y^{2} + 6 x - 2 y - 54 = 0

(x + 3)^{2} + (y - 4)^{2} = 16

What is the radius 74=(24-x)^2+(22-y)^2 ?
The radius 74=(24-x)^2+(22-y)^2 is r=sqrt(74)